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1412004444001 = 1823774549887
BaseRepresentation
bin10100100011000010000…
…001011111011101100001
311222222122000110201211221
4110203002001133131201
5141113241114202001
63000355455335041
7204004533513034
oct24430201373541
94888560421757
101412004444001
114a4911774798
121a97a5521481
13a31c7966388
144c4aca6301b
1526ae1eac1a1
hex148c205f761

1412004444001 has 4 divisors (see below), whose sum is σ = 1412778995712. Its totient is φ = 1411229892292.

The previous prime is 1412004443989. The next prime is 1412004444061. The reversal of 1412004444001 is 1004444002141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1412004444001 - 27 = 1412004443873 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1412004444061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387273121 + ... + 387276766.

It is an arithmetic number, because the mean of its divisors is an integer number (353194748928).

Almost surely, 21412004444001 is an apocalyptic number.

It is an amenable number.

1412004444001 is a deficient number, since it is larger than the sum of its proper divisors (774551711).

1412004444001 is an equidigital number, since it uses as much as digits as its factorization.

1412004444001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 774551710.

The product of its (nonzero) digits is 2048, while the sum is 25.

Adding to 1412004444001 its reverse (1004444002141), we get a palindrome (2416448446142).

The spelling of 1412004444001 in words is "one trillion, four hundred twelve billion, four million, four hundred forty-four thousand, one".

Divisors: 1 1823 774549887 1412004444001