Base | Representation |
---|---|
bin | 100000000110101111111111… |
… | …000111011101000101010111 |
3 | 200111221201022110120122212212 |
4 | 200012233333013131011113 |
5 | 122001420310440001330 |
6 | 1220150555010104035 |
7 | 41512313405561552 |
oct | 4006577707350527 |
9 | 614851273518785 |
10 | 141201330000215 |
11 | 40a9a169746171 |
12 | 13a0591b87b01b |
13 | 60a32c7708484 |
14 | 26c2276305699 |
15 | 114ce85d41295 |
hex | 806bff1dd157 |
141201330000215 has 4 divisors (see below), whose sum is σ = 169441596000264. Its totient is φ = 112961064000168.
The previous prime is 141201330000209. The next prime is 141201330000259. The reversal of 141201330000215 is 512000033102141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141201330000215 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14120133000017 + ... + 14120133000026.
It is an arithmetic number, because the mean of its divisors is an integer number (42360399000066).
Almost surely, 2141201330000215 is an apocalyptic number.
141201330000215 is a deficient number, since it is larger than the sum of its proper divisors (28240266000049).
141201330000215 is an equidigital number, since it uses as much as digits as its factorization.
141201330000215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28240266000048.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 141201330000215 its reverse (512000033102141), we get a palindrome (653201363102356).
The spelling of 141201330000215 in words is "one hundred forty-one trillion, two hundred one billion, three hundred thirty million, two hundred fifteen", and thus it is an aban number.
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