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14120145335 = 52824029067
BaseRepresentation
bin11010010011010000…
…00101000110110111
31100110001112200222202
431021220011012313
5212404224122320
610253043415115
71006624153322
oct151150050667
940401480882
1014120145335
115a964aa1aa
1228a098449b
131440486caa
1497d42d7b9
15579966b75
hex349a051b7

14120145335 has 4 divisors (see below), whose sum is σ = 16944174408. Its totient is φ = 11296116264.

The previous prime is 14120145331. The next prime is 14120145359. The reversal of 14120145335 is 53354102141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14120145335 - 22 = 14120145331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14120145298 and 14120145307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14120145331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1412014529 + ... + 1412014538.

It is an arithmetic number, because the mean of its divisors is an integer number (4236043602).

Almost surely, 214120145335 is an apocalyptic number.

14120145335 is a deficient number, since it is larger than the sum of its proper divisors (2824029073).

14120145335 is an equidigital number, since it uses as much as digits as its factorization.

14120145335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2824029072.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 14120145335 its reverse (53354102141), we get a palindrome (67474247476).

The spelling of 14120145335 in words is "fourteen billion, one hundred twenty million, one hundred forty-five thousand, three hundred thirty-five".

Divisors: 1 5 2824029067 14120145335