Search a number
-
+
14120211035 = 57403434601
BaseRepresentation
bin11010010011010000…
…10101001001011011
31100110001200001010002
431021220111021123
5212404233223120
610253045043215
71006624546010
oct151150251133
940401601102
1014120211035
115a965445a7
1228a09b650b
1314404aab78
1497d449707
1557997b375
hex349a1525b

14120211035 has 8 divisors (see below), whose sum is σ = 19364860896. Its totient is φ = 9682430400.

The previous prime is 14120211029. The next prime is 14120211103. The reversal of 14120211035 is 53011202141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14120211035 - 212 = 14120206939 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14120210998 and 14120211016.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201717266 + ... + 201717335.

It is an arithmetic number, because the mean of its divisors is an integer number (2420607612).

Almost surely, 214120211035 is an apocalyptic number.

14120211035 is a deficient number, since it is larger than the sum of its proper divisors (5244649861).

14120211035 is an equidigital number, since it uses as much as digits as its factorization.

14120211035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 403434613.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 14120211035 its reverse (53011202141), we get a palindrome (67131413176).

The spelling of 14120211035 in words is "fourteen billion, one hundred twenty million, two hundred eleven thousand, thirty-five".

Divisors: 1 5 7 35 403434601 2017173005 2824042207 14120211035