14120211103 has 2 divisors, whose sum is σ = 14120211104. Its totient is φ = 14120211102.

The previous prime is 14120211029. The next prime is 14120211107. The reversal of 14120211103 is 30111202141.

14120211103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (30111202141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14120211103 - 2¹³ = 14120202911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14120211107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060105551 + 7060105552.

It is an arithmetic number, because the mean of its divisors is an integer number (7060105552).

Almost surely, 2^14120211103 is an apocalyptic number.

14120211103 is a deficient number, since it is larger than the sum of its proper divisors (1).

14120211103 is an equidigital number, since it uses as much as digits as its factorization.

14120211103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 14120211103 its reverse (30111202141), we get a palindrome (44231413244).

The spelling of 14120211103 in words is "fourteen billion, one hundred twenty million, two hundred eleven thousand, one hundred three".