1412021314013 has 4 divisors (see below), whose sum is σ = 1412080470240. Its totient is φ = 1411962157788.

The previous prime is 1412021314003. The next prime is 1412021314061. The reversal of 1412021314013 is 3104131202141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1412021314013 - 2⁸ = 1412021313757 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1412021314013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412021314003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29542295 + ... + 29590052.

It is an arithmetic number, because the mean of its divisors is an integer number (353020117560).

Almost surely, 2^{1412021314013} is an apocalyptic number.

It is an amenable number.

1412021314013 is a deficient number, since it is larger than the sum of its proper divisors (59156227).

1412021314013 is an equidigital number, since it uses as much as digits as its factorization.

1412021314013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59156226.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1412021314013 its reverse (3104131202141), we get a palindrome (4516152516154).

The spelling of 1412021314013 in words is "one trillion, four hundred twelve billion, twenty-one million, three hundred fourteen thousand, thirteen".