141202244413001 has 4 divisors (see below), whose sum is σ = 141202720165632. Its totient is φ = 141201768660372.

The previous prime is 141202244412989. The next prime is 141202244413019. The reversal of 141202244413001 is 100314442202141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141202244413001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141202244413501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 237430841 + ... + 238024806.

It is an arithmetic number, because the mean of its divisors is an integer number (35300680041408).

Almost surely, 2^{141202244413001} is an apocalyptic number.

It is an amenable number.

141202244413001 is a deficient number, since it is larger than the sum of its proper divisors (475752631).

141202244413001 is an equidigital number, since it uses as much as digits as its factorization.

141202244413001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 475752630.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 141202244413001 its reverse (100314442202141), we get a palindrome (241516686615142).

The spelling of 141202244413001 in words is "one hundred forty-one trillion, two hundred two billion, two hundred forty-four million, four hundred thirteen thousand, one".