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141202244413002 = 2335965553502513
BaseRepresentation
bin100000000110110000110101…
…100111101010011001001010
3200111221210200012012122102010
4200012300311213222121022
5122001424144032204002
61220151225433120350
741512345151136213
oct4006606547523112
9614853605178363
10141202244413002
1140a9a598922013
1213a05b35b590b6
1360a3411caa126
1426c232193440a
15114cedb26846c
hex806c359ea64a

141202244413002 has 16 divisors (see below), whose sum is σ = 283191130860480. Its totient is φ = 46936307798592.

The previous prime is 141202244412989. The next prime is 141202244413019. The reversal of 141202244413002 is 200314442202141.

141202244413002 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32776749103 + ... + 32776753410.

It is an arithmetic number, because the mean of its divisors is an integer number (17699445678780).

Almost surely, 2141202244413002 is an apocalyptic number.

141202244413002 is an abundant number, since it is smaller than the sum of its proper divisors (141988886447478).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141202244413002 is a wasteful number, since it uses less digits than its factorization.

141202244413002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65553502877.

The product of its (nonzero) digits is 12288, while the sum is 30.

Adding to 141202244413002 its reverse (200314442202141), we get a palindrome (341516686615143).

The spelling of 141202244413002 in words is "one hundred forty-one trillion, two hundred two billion, two hundred forty-four million, four hundred thirteen thousand, two".

Divisors: 1 2 3 6 359 718 1077 2154 65553502513 131107005026 196660507539 393321015078 23533707402167 47067414804334 70601122206501 141202244413002