Base | Representation |
---|---|
bin | 11010010011010001… |
… | …10000110000001111 |
3 | 1100110001212210020002 |
4 | 31021220300300033 |
5 | 212404300332421 |
6 | 10253051314515 |
7 | 1006625526455 |
oct | 151150606017 |
9 | 40401783202 |
10 | 14120324111 |
11 | 5a96611553 |
12 | 28a0a4ba3b |
13 | 144051a48a |
14 | 97d4789d5 |
15 | 57999eb0b |
hex | 349a30c0f |
14120324111 has 4 divisors (see below), whose sum is σ = 14120638224. Its totient is φ = 14120010000.
The previous prime is 14120323999. The next prime is 14120324159. The reversal of 14120324111 is 11142302141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11142302141 = 3779 ⋅2948479.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120324111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14120324161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75515 + ... + 184236.
It is an arithmetic number, because the mean of its divisors is an integer number (3530159556).
Almost surely, 214120324111 is an apocalyptic number.
14120324111 is a deficient number, since it is larger than the sum of its proper divisors (314113).
14120324111 is an equidigital number, since it uses as much as digits as its factorization.
14120324111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 314112.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 14120324111 its reverse (11142302141), we get a palindrome (25262626252).
The spelling of 14120324111 in words is "fourteen billion, one hundred twenty million, three hundred twenty-four thousand, one hundred eleven".
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