Base | Representation |
---|---|
bin | 1000001110000001101… |
… | …0111001010001110011 |
3 | 111111110202102111201022 |
4 | 2003200122321101303 |
5 | 4303141222201321 |
6 | 144511313530055 |
7 | 13126112022356 |
oct | 2034032712163 |
9 | 444422374638 |
10 | 141204100211 |
11 | 54980040489 |
12 | 23448b7392b |
13 | 10414190825 |
14 | 6b9750829d |
15 | 3a167bbdab |
hex | 20e06b9473 |
141204100211 has 4 divisors (see below), whose sum is σ = 141530207112. Its totient is φ = 140877993312.
The previous prime is 141204100183. The next prime is 141204100217. The reversal of 141204100211 is 112001402141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141204100211 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 141204100211.
It is not an unprimeable number, because it can be changed into a prime (141204100217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163052801 + ... + 163053666.
It is an arithmetic number, because the mean of its divisors is an integer number (35382551778).
Almost surely, 2141204100211 is an apocalyptic number.
141204100211 is a deficient number, since it is larger than the sum of its proper divisors (326106901).
141204100211 is an equidigital number, since it uses as much as digits as its factorization.
141204100211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 326106900.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 141204100211 its reverse (112001402141), we get a palindrome (253205502352).
The spelling of 141204100211 in words is "one hundred forty-one billion, two hundred four million, one hundred thousand, two hundred eleven".
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