Base | Representation |
---|---|
bin | 11010010011010010… |
… | …00110100100001101 |
3 | 1100110002001022210001 |
4 | 31021221012210031 |
5 | 212404311212303 |
6 | 10253053244301 |
7 | 1006626351106 |
oct | 151151064415 |
9 | 40402038701 |
10 | 14120413453 |
11 | 5a96672693 |
12 | 28a0a93691 |
13 | 144054c043 |
14 | 97d49d3ad |
15 | 5799bb31d |
hex | 349a4690d |
14120413453 has 4 divisors (see below), whose sum is σ = 14131472220. Its totient is φ = 14109354688.
The previous prime is 14120413421. The next prime is 14120413457. The reversal of 14120413453 is 35431402141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5565458404 + 8554955049 = 74602^2 + 92493^2 .
It is a cyclic number.
It is not a de Polignac number, because 14120413453 - 25 = 14120413421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14120413457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5527468 + ... + 5530021.
It is an arithmetic number, because the mean of its divisors is an integer number (3532868055).
Almost surely, 214120413453 is an apocalyptic number.
It is an amenable number.
14120413453 is a deficient number, since it is larger than the sum of its proper divisors (11058767).
14120413453 is a wasteful number, since it uses less digits than its factorization.
14120413453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11058766.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 14120413453 its reverse (35431402141), we get a palindrome (49551815594).
The spelling of 14120413453 in words is "fourteen billion, one hundred twenty million, four hundred thirteen thousand, four hundred fifty-three".
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