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1412100122113 = 41106944637219
BaseRepresentation
bin10100100011000111101…
…110011110011000000001
311222222212200111200112201
4110203013232132120001
5141113440112401423
63000413154153201
7204010104665002
oct24430756363001
94888780450481
101412100122113
114a496078410a
121a9811582801
13a3211725945
144c4bb64b1a9
1526aea5ab2ad
hex148c7b9e601

1412100122113 has 16 divisors (see below), whose sum is σ = 1448419795200. Its totient is φ = 1375870907520.

The previous prime is 1412100122101. The next prime is 1412100122129. The reversal of 1412100122113 is 3112210012141.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1412100122113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1412100122183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 195605218 + ... + 195612436.

It is an arithmetic number, because the mean of its divisors is an integer number (90526237200).

Almost surely, 21412100122113 is an apocalyptic number.

It is an amenable number.

1412100122113 is a deficient number, since it is larger than the sum of its proper divisors (36319673087).

1412100122113 is a wasteful number, since it uses less digits than its factorization.

1412100122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12792.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1412100122113 its reverse (3112210012141), we get a palindrome (4524310134254).

The spelling of 1412100122113 in words is "one trillion, four hundred twelve billion, one hundred million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 41 1069 4463 7219 43829 182983 295979 4770947 7717111 32218397 195608827 316401551 1320954277 34441466393 1412100122113