Base | Representation |
---|---|
bin | 100000000110111001000110… |
… | …000111000111110101110101 |
3 | 200111222122120010022110112012 |
4 | 200012321012013013311311 |
5 | 122002100323410431013 |
6 | 1220155253331334005 |
7 | 41513110654140014 |
oct | 4006710607076565 |
9 | 614878503273465 |
10 | 141211111030133 |
11 | 40aa33288a0771 |
12 | 13a077ab451305 |
13 | 60a41c5c28c41 |
14 | 26c2923348a7b |
15 | 114d3598991a8 |
hex | 806e461c7d75 |
141211111030133 has 8 divisors (see below), whose sum is σ = 149522880683520. Its totient is φ = 132899922900160.
The previous prime is 141211111030103. The next prime is 141211111030163. The reversal of 141211111030133 is 331030111112141.
It is an interprime number because it is at equal distance from previous prime (141211111030103) and next prime (141211111030163).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 141211111030133 - 234 = 141193931160949 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 141211111030099 and 141211111030108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141211111030103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 144880853 + ... + 145852266.
It is an arithmetic number, because the mean of its divisors is an integer number (18690360085440).
Almost surely, 2141211111030133 is an apocalyptic number.
It is an amenable number.
141211111030133 is a deficient number, since it is larger than the sum of its proper divisors (8311769653387).
141211111030133 is a wasteful number, since it uses less digits than its factorization.
141211111030133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 290761707.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 141211111030133 its reverse (331030111112141), we get a palindrome (472241222142274).
The spelling of 141211111030133 in words is "one hundred forty-one trillion, two hundred eleven billion, one hundred eleven million, thirty thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •