141211312440111 has 8 divisors (see below), whose sum is σ = 209201944355760. Its totient is φ = 94140874960056.

The previous prime is 141211312440109. The next prime is 141211312440137. The reversal of 141211312440111 is 111044213112141.

141211312440111 is a `hidden beast` number, since 1 + 4 + 1 + 211 + 3 + 1 + 2 + 440 + 1 + 1 + 1 = 666.

It is not a de Polignac number, because 141211312440111 - 2¹ = 141211312440109 is a prime.

It is a super-2 number, since 2×141211312440111² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 5230048608893 = 141211312440111 / (1 + 4 + 1 + 2 + 1 + 1 + 3 + 1 + 2 + 4 + 4 + 0 + 1 + 1 + 1).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141211312440101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2615024304420 + ... + 2615024304473.

It is an arithmetic number, because the mean of its divisors is an integer number (26150243044470).

Almost surely, 2^{141211312440111} is an apocalyptic number.

141211312440111 is a deficient number, since it is larger than the sum of its proper divisors (67990631915649).

141211312440111 is an equidigital number, since it uses as much as digits as its factorization.

141211312440111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5230048608902 (or 5230048608896 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 27.

Adding to 141211312440111 its reverse (111044213112141), we get a palindrome (252255525552252).

The spelling of 141211312440111 in words is "one hundred forty-one trillion, two hundred eleven billion, three hundred twelve million, four hundred forty thousand, one hundred eleven".