141211400131021 has 4 divisors (see below), whose sum is σ = 154048800142944. Its totient is φ = 128374000119100.

The previous prime is 141211400130869. The next prime is 141211400131031. The reversal of 141211400131021 is 120131004112141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141211400131021 - 2²⁹ = 141210863260109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141211400130983 and 141211400131001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141211400131031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6418700005945 + ... + 6418700005966.

It is an arithmetic number, because the mean of its divisors is an integer number (38512200035736).

Almost surely, 2^{141211400131021} is an apocalyptic number.

141211400131021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

141211400131021 is a deficient number, since it is larger than the sum of its proper divisors (12837400011923).

141211400131021 is a wasteful number, since it uses less digits than its factorization.

141211400131021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12837400011922.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 141211400131021 its reverse (120131004112141), we get a palindrome (261342404243162).

The spelling of 141211400131021 in words is "one hundred forty-one trillion, two hundred eleven billion, four hundred million, one hundred thirty-one thousand, twenty-one".