Base | Representation |
---|---|
bin | 1100110101111101011011… |
… | …0100010111010100000010 |
3 | 1211222222012000202120122011 |
4 | 3031133112310113110002 |
5 | 3322330114324200104 |
6 | 50011101055403134 |
7 | 2655135355512235 |
oct | 315372664272402 |
9 | 54888160676564 |
10 | 14121161553154 |
11 | 4554829616897 |
12 | 17009385234aa |
13 | 7b5809990b76 |
14 | 36b679b7741c |
15 | 1974ccd47904 |
hex | cd7d6d17502 |
14121161553154 has 4 divisors (see below), whose sum is σ = 21181742329734. Its totient is φ = 7060580776576.
The previous prime is 14121161553143. The next prime is 14121161553197. The reversal of 14121161553154 is 45135516112141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9327667299129 + 4793494254025 = 3054123^2 + 2189405^2 .
It is a super-2 number, since 2×141211615531542 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3530290388287 + ... + 3530290388290.
Almost surely, 214121161553154 is an apocalyptic number.
14121161553154 is a deficient number, since it is larger than the sum of its proper divisors (7060580776580).
14121161553154 is an equidigital number, since it uses as much as digits as its factorization.
14121161553154 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7060580776579.
The product of its digits is 72000, while the sum is 40.
Adding to 14121161553154 its reverse (45135516112141), we get a palindrome (59256677665295).
The spelling of 14121161553154 in words is "fourteen trillion, one hundred twenty-one billion, one hundred sixty-one million, five hundred fifty-three thousand, one hundred fifty-four".
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