1412132652071 has 4 divisors (see below), whose sum is σ = 1412135315112. Its totient is φ = 1412129989032.

The previous prime is 1412132652041. The next prime is 1412132652079. The reversal of 1412132652071 is 1702562312141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1412132652071 - 2¹⁰ = 1412132651047 is a prime.

It is a super-3 number, since 3×1412132652071³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412132652079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235256 + ... + 1696941.

It is an arithmetic number, because the mean of its divisors is an integer number (353033828778).

Almost surely, 2^{1412132652071} is an apocalyptic number.

1412132652071 is a deficient number, since it is larger than the sum of its proper divisors (2663041).

1412132652071 is an equidigital number, since it uses as much as digits as its factorization.

1412132652071 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2663040.

The product of its (nonzero) digits is 20160, while the sum is 35.

The spelling of 1412132652071 in words is "one trillion, four hundred twelve billion, one hundred thirty-two million, six hundred fifty-two thousand, seventy-one".