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141214240201203 = 33133715817687457
BaseRepresentation
bin100000000110111100000000…
…100111111101100111110011
3200111222221122012101211021000
4200012330000213331213303
5122002123230442414303
61220200532032333043
741513251341511521
oct4006740047754763
9614887565354230
10141214240201203
1140aa4694167264
1213a083233a4183
1360a45a42c8860
1426c2b3cb77311
15114d48e455da3
hex806f009fd9f3

141214240201203 has 64 divisors (see below), whose sum is σ = 231403202504320. Its totient is φ = 84546924650496.

The previous prime is 141214240201201. The next prime is 141214240201213. The reversal of 141214240201203 is 302102042412141.

141214240201203 is a `hidden beast` number, since 1 + 4 + 1 + 2 + 14 + 240 + 201 + 203 = 666.

141214240201203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 141214240201203 - 21 = 141214240201201 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141214240201201) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 205071651 + ... + 205759107.

It is an arithmetic number, because the mean of its divisors is an integer number (3615675039130).

Almost surely, 2141214240201203 is an apocalyptic number.

141214240201203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

141214240201203 is a deficient number, since it is larger than the sum of its proper divisors (90188962303117).

141214240201203 is a wasteful number, since it uses less digits than its factorization.

141214240201203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 703333 (or 703327 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 141214240201203 its reverse (302102042412141), we get a palindrome (443316282613344).

The spelling of 141214240201203 in words is "one hundred forty-one trillion, two hundred fourteen billion, two hundred forty million, two hundred one thousand, two hundred three".

Divisors: 1 3 9 13 27 37 39 111 117 333 351 481 999 1443 4329 12987 15817 47451 142353 205621 427059 585229 616863 687457 1755687 1850589 2062371 5267061 5551767 6187113 7607977 8936941 15801183 18561339 22823931 25435909 26810823 68471793 76307727 80432469 205415379 228923181 241297407 330666817 686769543 992000451 2976001353 8928004059 10873507369 32620522107 97861566321 141355595797 293584698963 402319772653 424066787391 1206959317959 1272200362173 3620877953877 3816601086519 5230157044489 10862633861631 15690471133467 47071413400401 141214240201203