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14122145041 = 61323037757
BaseRepresentation
bin11010010011011111…
…01101010100010001
31100110012022022001221
431021233231110101
5212410232120131
610253154325041
71006650152344
oct151157552421
940405268057
1014122145041
115a97645654
1228a1589781
131440a07254
1497d7d045b
15579c0e411
hex349bed511

14122145041 has 4 divisors (see below), whose sum is σ = 14145183412. Its totient is φ = 14099106672.

The previous prime is 14122145003. The next prime is 14122145099. The reversal of 14122145041 is 14054122141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6152833600 + 7969311441 = 78440^2 + 89271^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14122145041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14122144997 and 14122145015.

It is not an unprimeable number, because it can be changed into a prime (14122140041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11518266 + ... + 11519491.

It is an arithmetic number, because the mean of its divisors is an integer number (3536295853).

Almost surely, 214122145041 is an apocalyptic number.

It is an amenable number.

14122145041 is a deficient number, since it is larger than the sum of its proper divisors (23038371).

14122145041 is an equidigital number, since it uses as much as digits as its factorization.

14122145041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23038370.

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 14122145041 its reverse (14054122141), we get a palindrome (28176267182).

The spelling of 14122145041 in words is "fourteen billion, one hundred twenty-two million, one hundred forty-five thousand, forty-one".

Divisors: 1 613 23037757 14122145041