14123052025141 has 4 divisors (see below), whose sum is σ = 14866370552800. Its totient is φ = 13379733497484.

The previous prime is 14123052025139. The next prime is 14123052025171. The reversal of 14123052025141 is 14152025032141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14123052025141 - 2¹ = 14123052025139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14123052025171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371659263801 + ... + 371659263838.

It is an arithmetic number, because the mean of its divisors is an integer number (3716592638200).

Almost surely, 2^{14123052025141} is an apocalyptic number.

It is an amenable number.

14123052025141 is a deficient number, since it is larger than the sum of its proper divisors (743318527659).

14123052025141 is an equidigital number, since it uses as much as digits as its factorization.

14123052025141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 743318527658.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 14123052025141 its reverse (14152025032141), we get a palindrome (28275077057282).

The spelling of 14123052025141 in words is "fourteen trillion, one hundred twenty-three billion, fifty-two million, twenty-five thousand, one hundred forty-one".