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14123053131 = 311427971307
BaseRepresentation
bin11010010011100110…
…01011000001001011
31100110021000102201220
431021303023001023
5212411000200011
610253230013123
71006660654005
oct151163130113
940407012656
1014123053131
115a98105940
1228a19471a3
131440c64695
1497d989375
15579d3d506
hex349ccb04b

14123053131 has 8 divisors (see below), whose sum is σ = 20542622784. Its totient is φ = 8559426120.

The previous prime is 14123053037. The next prime is 14123053177. The reversal of 14123053131 is 13135032141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14123053131 - 27 = 14123053003 is a prime.

It is a super-2 number, since 2×141230531312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14123053531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 213985621 + ... + 213985686.

It is an arithmetic number, because the mean of its divisors is an integer number (2567827848).

Almost surely, 214123053131 is an apocalyptic number.

14123053131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14123053131 is a deficient number, since it is larger than the sum of its proper divisors (6419569653).

14123053131 is a wasteful number, since it uses less digits than its factorization.

14123053131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 427971321.

The product of its (nonzero) digits is 1080, while the sum is 24.

Adding to 14123053131 its reverse (13135032141), we get a palindrome (27258085272).

The spelling of 14123053131 in words is "fourteen billion, one hundred twenty-three million, fifty-three thousand, one hundred thirty-one".

Divisors: 1 3 11 33 427971307 1283913921 4707684377 14123053131