14123255232141 has 36 divisors (see below), whose sum is σ = 22474502770720. Its totient is φ = 8540050503600.

The previous prime is 14123255232077. The next prime is 14123255232143.

14123255232141 is a `hidden beast` number, since 1 + 4 + 1 + 2 + 32 + 552 + 32 + 1 + 41 = 666.

14123255232141 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 14123255232141 - 2⁶ = 14123255232077 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14123255232096 and 14123255232105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14123255232143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 14293015 + ... + 15249156.

Almost surely, 2^{14123255232141} is an apocalyptic number.

14123255232141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14123255232141 is a deficient number, since it is larger than the sum of its proper divisors (8351247538579).

14123255232141 is a wasteful number, since it uses less digits than its factorization.

14123255232141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29542638 (or 29542624 counting only the distinct ones).

The product of its digits is 57600, while the sum is 36.

It can be divided in two parts, 1412325 and 5232141, that added together give a palindrome (6644466).

The spelling of 14123255232141 in words is "fourteen trillion, one hundred twenty-three billion, two hundred fifty-five million, two hundred thirty-two thousand, one hundred forty-one".