14124443340401 has 4 divisors (see below), whose sum is σ = 14232263518704. Its totient is φ = 14016623162100.

The previous prime is 14124443340389. The next prime is 14124443340433. The reversal of 14124443340401 is 10404334442141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14124443340401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14124443840401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53910088955 + ... + 53910089216.

It is an arithmetic number, because the mean of its divisors is an integer number (3558065879676).

Almost surely, 2^{14124443340401} is an apocalyptic number.

It is an amenable number.

14124443340401 is a deficient number, since it is larger than the sum of its proper divisors (107820178303).

14124443340401 is a wasteful number, since it uses less digits than its factorization.

14124443340401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107820178302.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 14124443340401 its reverse (10404334442141), we get a palindrome (24528777782542).

The spelling of 14124443340401 in words is "fourteen trillion, one hundred twenty-four billion, four hundred forty-three million, three hundred forty thousand, four hundred one".