Base | Representation |
---|---|
bin | 1100110110001011101110… |
… | …1100010001010110100011 |
3 | 1212000100002122010201112102 |
4 | 3031202323230101112203 |
5 | 3322411000330222201 |
6 | 50012534105121015 |
7 | 2655332463010043 |
oct | 315427354212643 |
9 | 55010078121472 |
10 | 14125001414051 |
11 | 455641a073150 |
12 | 170162a48916b |
13 | 7b5c9c3736c8 |
14 | 36b921b23723 |
15 | 197654ed926b |
hex | cd8bbb115a3 |
14125001414051 has 32 divisors (see below), whose sum is σ = 15950292906240. Its totient is φ = 12397059763200.
The previous prime is 14125001414039. The next prime is 14125001414089. The reversal of 14125001414051 is 15041410052141.
It is a cyclic number.
It is not a de Polignac number, because 14125001414051 - 226 = 14124934305187 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14125001414021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18878555 + ... + 19612491.
It is an arithmetic number, because the mean of its divisors is an integer number (498446653320).
Almost surely, 214125001414051 is an apocalyptic number.
14125001414051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14125001414051 is a deficient number, since it is larger than the sum of its proper divisors (1825291492189).
14125001414051 is a wasteful number, since it uses less digits than its factorization.
14125001414051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 734435.
The product of its (nonzero) digits is 3200, while the sum is 29.
Adding to 14125001414051 its reverse (15041410052141), we get a palindrome (29166411466192).
The spelling of 14125001414051 in words is "fourteen trillion, one hundred twenty-five billion, one million, four hundred fourteen thousand, fifty-one".
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