14125001540131 has 4 divisors (see below), whose sum is σ = 14125219647264. Its totient is φ = 14124783433000.

The previous prime is 14125001540123. The next prime is 14125001540141. The reversal of 14125001540131 is 13104510052141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14125001540131 - 2³ = 14125001540123 is a prime.

It is a super-2 number, since 2×14125001540131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14125001540131.

It is not an unprimeable number, because it can be changed into a prime (14125001540141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108956395 + ... + 109085956.

It is an arithmetic number, because the mean of its divisors is an integer number (3531304911816).

Almost surely, 2^{14125001540131} is an apocalyptic number.

14125001540131 is a deficient number, since it is larger than the sum of its proper divisors (218107133).

14125001540131 is an equidigital number, since it uses as much as digits as its factorization.

14125001540131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 218107132.

The product of its (nonzero) digits is 2400, while the sum is 28.

Adding to 14125001540131 its reverse (13104510052141), we get a palindrome (27229511592272).

The spelling of 14125001540131 in words is "fourteen trillion, one hundred twenty-five billion, one million, five hundred forty thousand, one hundred thirty-one".