14125003404031 has 6 divisors (see below), whose sum is σ = 15295122029400. Its totient is φ = 13038464680488.

The previous prime is 14125003404011. The next prime is 14125003404079. The reversal of 14125003404031 is 13040430052141.

It is not a de Polignac number, because 14125003404031 - 2¹⁷ = 14125003272959 is a prime.

It is a super-2 number, since 2×14125003404031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14125003404011) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 41789950731 + ... + 41789951068.

It is an arithmetic number, because the mean of its divisors is an integer number (2549187004900).

Almost surely, 2^{14125003404031} is an apocalyptic number.

14125003404031 is a deficient number, since it is larger than the sum of its proper divisors (1170118625369).

14125003404031 is an equidigital number, since it uses as much as digits as its factorization.

14125003404031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83579901825 (or 83579901812 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 14125003404031 its reverse (13040430052141), we get a palindrome (27165433456172).

The spelling of 14125003404031 in words is "fourteen trillion, one hundred twenty-five billion, three million, four hundred four thousand, thirty-one".