Search a number
-
+
1412502543613 = 7201786077659
BaseRepresentation
bin10100100011011111101…
…101100101110011111101
312000000220201201211001201
4110203133231211303331
5141120301122343423
63000521131335501
7204023062343350
oct24433755456375
95000821654051
101412502543613
114a5047953367
121a99042b1591
13a3276c04485
144c518c82297
1526b20a9c2ad
hex148dfb65cfd

1412502543613 has 4 divisors (see below), whose sum is σ = 1614288621280. Its totient is φ = 1210716465948.

The previous prime is 1412502543563. The next prime is 1412502543629. The reversal of 1412502543613 is 3163452052141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1412502543613 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412502543643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100893038823 + ... + 100893038836.

It is an arithmetic number, because the mean of its divisors is an integer number (403572155320).

Almost surely, 21412502543613 is an apocalyptic number.

It is an amenable number.

1412502543613 is a deficient number, since it is larger than the sum of its proper divisors (201786077667).

1412502543613 is an equidigital number, since it uses as much as digits as its factorization.

1412502543613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 201786077666.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 1412502543613 its reverse (3163452052141), we get a palindrome (4575954595754).

The spelling of 1412502543613 in words is "one trillion, four hundred twelve billion, five hundred two million, five hundred forty-three thousand, six hundred thirteen".

Divisors: 1 7 201786077659 1412502543613