Base | Representation |
---|---|
bin | 11010010011110111… |
… | …10010100000110011 |
3 | 1100110102021012101121 |
4 | 31021323302200303 |
5 | 212412034441201 |
6 | 10253350243111 |
7 | 1010016112534 |
oct | 151173624063 |
9 | 40412235347 |
10 | 14125312051 |
11 | 5a99409014 |
12 | 28a2656497 |
13 | 1441575916 |
14 | 97ddb668b |
15 | 57a1379a1 |
hex | 349ef2833 |
14125312051 has 4 divisors (see below), whose sum is σ = 14336137672. Its totient is φ = 13914486432.
The previous prime is 14125312049. The next prime is 14125312079. The reversal of 14125312051 is 15021352141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14125312051 - 21 = 14125312049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14125312001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105412710 + ... + 105412843.
It is an arithmetic number, because the mean of its divisors is an integer number (3584034418).
Almost surely, 214125312051 is an apocalyptic number.
14125312051 is a deficient number, since it is larger than the sum of its proper divisors (210825621).
14125312051 is an equidigital number, since it uses as much as digits as its factorization.
14125312051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 210825620.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 14125312051 its reverse (15021352141), we get a palindrome (29146664192).
The spelling of 14125312051 in words is "fourteen billion, one hundred twenty-five million, three hundred twelve thousand, fifty-one".
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