14125453135333 has 4 divisors (see below), whose sum is σ = 14126945848288. Its totient is φ = 14123960422380.

The previous prime is 14125453135301. The next prime is 14125453135363. The reversal of 14125453135333 is 33353135452141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14125453135333 - 2⁵ = 14125453135301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14125453135333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14125453135363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 746342283 + ... + 746361208.

It is an arithmetic number, because the mean of its divisors is an integer number (3531736462072).

Almost surely, 2^{14125453135333} is an apocalyptic number.

It is an amenable number.

14125453135333 is a deficient number, since it is larger than the sum of its proper divisors (1492712955).

14125453135333 is an equidigital number, since it uses as much as digits as its factorization.

14125453135333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1492712954.

The product of its digits is 972000, while the sum is 43.

Adding to 14125453135333 its reverse (33353135452141), we get a palindrome (47478588587474).

The spelling of 14125453135333 in words is "fourteen trillion, one hundred twenty-five billion, four hundred fifty-three million, one hundred thirty-five thousand, three hundred thirty-three".