Base | Representation |
---|---|
bin | 1100110110001101101011… |
… | …1001100110111101100101 |
3 | 1212000101110010100212002200 |
4 | 3031203122321212331211 |
5 | 3322413033400113013 |
6 | 50013102051325113 |
7 | 2655351451314534 |
oct | 315433271467545 |
9 | 55011403325080 |
10 | 14125525004133 |
11 | 4556668682124 |
12 | 17017558b0799 |
13 | 7b605399801a |
14 | 36b97149a31b |
15 | 197685e61e73 |
hex | cd8dae66f65 |
14125525004133 has 12 divisors (see below), whose sum is σ = 20408572836288. Its totient is φ = 9414692029800.
The previous prime is 14125525004131. The next prime is 14125525004137. The reversal of 14125525004133 is 33140052552141.
14125525004133 is a `hidden beast` number, since 1 + 4 + 12 + 5 + 5 + 2 + 500 + 4 + 133 = 666.
It is not a de Polignac number, because 14125525004133 - 21 = 14125525004131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14125525004131) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 193681485 + ... + 193754402.
It is an arithmetic number, because the mean of its divisors is an integer number (1700714403024).
Almost surely, 214125525004133 is an apocalyptic number.
It is an amenable number.
14125525004133 is a deficient number, since it is larger than the sum of its proper divisors (6283047832155).
14125525004133 is a wasteful number, since it uses less digits than its factorization.
14125525004133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 387439944 (or 387439941 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 14125525004133 its reverse (33140052552141), we get a palindrome (47265577556274).
The spelling of 14125525004133 in words is "fourteen trillion, one hundred twenty-five billion, five hundred twenty-five million, four thousand, one hundred thirty-three".
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