Base | Representation |
---|---|
bin | 100000000111100111000001… |
… | …111100010010010000011011 |
3 | 200112011100212110200111211202 |
4 | 200013213001330102100123 |
5 | 122003402331400014001 |
6 | 1220234051440544415 |
7 | 41516505135534014 |
oct | 4007470174222033 |
9 | 615140773614752 |
10 | 141260433204251 |
11 | 4101223898a139 |
12 | 13a1527532210b |
13 | 60a8a5642145a |
14 | 26c5081a3400b |
15 | 114e79499b96b |
hex | 8079c1f1241b |
141260433204251 has 4 divisors (see below), whose sum is σ = 148695192846600. Its totient is φ = 133825673561904.
The previous prime is 141260433204229. The next prime is 141260433204299. The reversal of 141260433204251 is 152402334062141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141260433204251 - 242 = 136862386693147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141260430204251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3717379821146 + ... + 3717379821183.
It is an arithmetic number, because the mean of its divisors is an integer number (37173798211650).
Almost surely, 2141260433204251 is an apocalyptic number.
141260433204251 is a deficient number, since it is larger than the sum of its proper divisors (7434759642349).
141260433204251 is an equidigital number, since it uses as much as digits as its factorization.
141260433204251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7434759642348.
The product of its (nonzero) digits is 138240, while the sum is 38.
Adding to 141260433204251 its reverse (152402334062141), we get a palindrome (293662767266392).
The spelling of 141260433204251 in words is "one hundred forty-one trillion, two hundred sixty billion, four hundred thirty-three million, two hundred four thousand, two hundred fifty-one".
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