Base | Representation |
---|---|
bin | 10100100011100111100… |
… | …011011101010100001111 |
3 | 12000001020220021211111111 |
4 | 110203213203131110033 |
5 | 141121033312330403 |
6 | 3000542151232451 |
7 | 204026250526504 |
oct | 24434743352417 |
9 | 5001226254444 |
10 | 1412634105103 |
11 | 4a5105141471 |
12 | 1a9940378727 |
13 | a3298248900 |
14 | 4c52c52b4ab |
15 | 26b2c3d856d |
hex | 148e78dd50f |
1412634105103 has 12 divisors (see below), whose sum is σ = 1529812619400. Its totient is φ = 1303837325856.
The previous prime is 1412634105101. The next prime is 1412634105137. The reversal of 1412634105103 is 3015014362141.
It is not a de Polignac number, because 1412634105103 - 21 = 1412634105101 is a prime.
It is a super-2 number, since 2×14126341051032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1412634105101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1261300 + ... + 2101462.
It is an arithmetic number, because the mean of its divisors is an integer number (127484384950).
Almost surely, 21412634105103 is an apocalyptic number.
1412634105103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1412634105103 is a deficient number, since it is larger than the sum of its proper divisors (117178514297).
1412634105103 is an equidigital number, since it uses as much as digits as its factorization.
1412634105103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 850138 (or 850125 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 1412634105103 its reverse (3015014362141), we get a palindrome (4427648467244).
The spelling of 1412634105103 in words is "one trillion, four hundred twelve billion, six hundred thirty-four million, one hundred five thousand, one hundred three".
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