14126421231131 has 4 divisors (see below), whose sum is σ = 15410641343064. Its totient is φ = 12842201119200.

The previous prime is 14126421231127. The next prime is 14126421231157. The reversal of 14126421231131 is 13113212462141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14126421231131 - 2² = 14126421231127 is a prime.

It is a super-2 number, since 2×14126421231131² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14126421231161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642110055950 + ... + 642110055971.

It is an arithmetic number, because the mean of its divisors is an integer number (3852660335766).

Almost surely, 2^{14126421231131} is an apocalyptic number.

14126421231131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14126421231131 is a deficient number, since it is larger than the sum of its proper divisors (1284220111933).

14126421231131 is a wasteful number, since it uses less digits than its factorization.

14126421231131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1284220111932.

The product of its digits is 6912, while the sum is 32.

Adding to 14126421231131 its reverse (13113212462141), we get a palindrome (27239633693272).

The spelling of 14126421231131 in words is "fourteen trillion, one hundred twenty-six billion, four hundred twenty-one million, two hundred thirty-one thousand, one hundred thirty-one".