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141300220211 = 1333710594603
BaseRepresentation
bin1000001110011000100…
…1100100000100110011
3111111201110021220120022
42003212021210010303
54303340324021321
6144525030034055
713131360024533
oct2034611440463
9444643256508
10141300220211
1154a1a3218a7
12234751a892b
131042b076277
146ba61a94c3
153a1ee56dab
hex20e6264133

141300220211 has 4 divisors (see below), whose sum is σ = 141310828152. Its totient is φ = 141289612272.

The previous prime is 141300220183. The next prime is 141300220213. The reversal of 141300220211 is 112022003141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141300220211 - 234 = 124120351027 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 141300220211.

It is not an unprimeable number, because it can be changed into a prime (141300220213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5283965 + ... + 5310638.

It is an arithmetic number, because the mean of its divisors is an integer number (35327707038).

Almost surely, 2141300220211 is an apocalyptic number.

141300220211 is a deficient number, since it is larger than the sum of its proper divisors (10607941).

141300220211 is a wasteful number, since it uses less digits than its factorization.

141300220211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10607940.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 141300220211 its reverse (112022003141), we get a palindrome (253322223352).

The spelling of 141300220211 in words is "one hundred forty-one billion, three hundred million, two hundred twenty thousand, two hundred eleven".

Divisors: 1 13337 10594603 141300220211