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14130031143 = 35578456033
BaseRepresentation
bin11010010100011011…
…10010101000100111
31100110202010221202210
431022031302220213
5212414241444033
610254035334503
71010104166034
oct151215625047
940422127683
1014130031143
115aa1041598
1228a4151433
131442538897
1498088438b
1557a76ad63
hex34a372a27

14130031143 has 8 divisors (see below), whose sum is σ = 18873867888. Its totient is φ = 9403107584.

The previous prime is 14130031061. The next prime is 14130031159. The reversal of 14130031143 is 34113003141.

14130031143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14130031143 - 29 = 14130030631 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14130031943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4226346 + ... + 4229687.

It is an arithmetic number, because the mean of its divisors is an integer number (2359233486).

Almost surely, 214130031143 is an apocalyptic number.

14130031143 is a deficient number, since it is larger than the sum of its proper divisors (4743836745).

14130031143 is an equidigital number, since it uses as much as digits as its factorization.

14130031143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8456593.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 14130031143 its reverse (34113003141), we get a palindrome (48243034284).

The spelling of 14130031143 in words is "fourteen billion, one hundred thirty million, thirty-one thousand, one hundred forty-three".

Divisors: 1 3 557 1671 8456033 25368099 4710010381 14130031143