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14130034453 = 31683667361
BaseRepresentation
bin11010010100011011…
…10011011100010101
31100110202011010022101
431022031303130111
5212414242100303
610254035402101
71010104211503
oct151215633425
940422133271
1014130034453
115aa1044027
1228a4153331
13144253a242
14980885673
1557a76bd1d
hex34a373715

14130034453 has 8 divisors (see below), whose sum is σ = 14607219456. Its totient is φ = 13654185600.

The previous prime is 14130034447. The next prime is 14130034459. The reversal of 14130034453 is 35443003141.

It is an interprime number because it is at equal distance from previous prime (14130034447) and next prime (14130034459).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14130034453 - 221 = 14127937301 is a prime.

It is a super-3 number, since 3×141300344533 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14130034459) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 312508 + ... + 354853.

It is an arithmetic number, because the mean of its divisors is an integer number (1825902432).

Almost surely, 214130034453 is an apocalyptic number.

It is an amenable number.

14130034453 is a deficient number, since it is larger than the sum of its proper divisors (477185003).

14130034453 is an equidigital number, since it uses as much as digits as its factorization.

14130034453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 668075.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 14130034453 its reverse (35443003141), we get a palindrome (49573037594).

The spelling of 14130034453 in words is "fourteen billion, one hundred thirty million, thirty-four thousand, four hundred fifty-three".

Divisors: 1 31 683 21173 667361 20688191 455807563 14130034453