Base | Representation |
---|---|
bin | 10100100011111101100… |
… | …110100100111011000001 |
3 | 12000002012200100112022121 |
4 | 110203331212210323001 |
5 | 141122313012141231 |
6 | 3001043004004241 |
7 | 204041362004005 |
oct | 24437546447301 |
9 | 5002180315277 |
10 | 1413004021441 |
11 | 4a5284a2a051 |
12 | 1a9a24230681 |
13 | a3326a8610c |
14 | 4c565700705 |
15 | 26b4eb08311 |
hex | 148fd9a4ec1 |
1413004021441 has 8 divisors (see below), whose sum is σ = 1415023069824. Its totient is φ = 1410985181760.
The previous prime is 1413004021393. The next prime is 1413004021483. The reversal of 1413004021441 is 1441204003141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1413004021441 - 211 = 1413004019393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1413004031441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17839596 + ... + 17918626.
It is an arithmetic number, because the mean of its divisors is an integer number (176877883728).
Almost surely, 21413004021441 is an apocalyptic number.
It is an amenable number.
1413004021441 is a deficient number, since it is larger than the sum of its proper divisors (2019048383).
1413004021441 is an equidigital number, since it uses as much as digits as its factorization.
1413004021441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104351.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1413004021441 its reverse (1441204003141), we get a palindrome (2854208024582).
The spelling of 1413004021441 in words is "one trillion, four hundred thirteen billion, four million, twenty-one thousand, four hundred forty-one".
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