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14130042245 = 511256909859
BaseRepresentation
bin11010010100011011…
…10101010110000101
31100110202011111222222
431022031311112011
5212414242322440
610254035502125
71010104243304
oct151215652605
940422144888
1014130042245
115aa1049970
1228a4157945
131442540957
1498088843b
1557a76e2b5
hex34a375585

14130042245 has 8 divisors (see below), whose sum is σ = 18497509920. Its totient is φ = 10276394320.

The previous prime is 14130042229. The next prime is 14130042253. The reversal of 14130042245 is 54224003141.

14130042245 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14130042245 - 24 = 14130042229 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128454875 + ... + 128454984.

It is an arithmetic number, because the mean of its divisors is an integer number (2312188740).

Almost surely, 214130042245 is an apocalyptic number.

It is an amenable number.

14130042245 is a deficient number, since it is larger than the sum of its proper divisors (4367467675).

14130042245 is a wasteful number, since it uses less digits than its factorization.

14130042245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 256909875.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 14130042245 its reverse (54224003141), we get a palindrome (68354045386).

The spelling of 14130042245 in words is "fourteen billion, one hundred thirty million, forty-two thousand, two hundred forty-five".

Divisors: 1 5 11 55 256909859 1284549295 2826008449 14130042245