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1413011025311 = 5821242743691
BaseRepresentation
bin10100100011111110000…
…001010010110110011111
312000002020011112100211012
4110203332001102312133
5141122321310302221
63001043414045435
7204041505354314
oct24437601226637
95002204470735
101413011025311
114a5288983176
121a9a2664987b
13a3328369012
144c566604d0b
1526b5053d65b
hex148fe052d9f

1413011025311 has 4 divisors (see below), whose sum is σ = 1413253774824. Its totient is φ = 1412768275800.

The previous prime is 1413011025301. The next prime is 1413011025323. The reversal of 1413011025311 is 1135201103141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413011025311 - 234 = 1395831156127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413011025301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121366025 + ... + 121377666.

It is an arithmetic number, because the mean of its divisors is an integer number (353313443706).

Almost surely, 21413011025311 is an apocalyptic number.

1413011025311 is a deficient number, since it is larger than the sum of its proper divisors (242749513).

1413011025311 is an equidigital number, since it uses as much as digits as its factorization.

1413011025311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242749512.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 1413011025311 its reverse (1135201103141), we get a palindrome (2548212128452).

The spelling of 1413011025311 in words is "one trillion, four hundred thirteen billion, eleven million, twenty-five thousand, three hundred eleven".

Divisors: 1 5821 242743691 1413011025311