Base | Representation |
---|---|
bin | 11010010100011110… |
… | …10110100110111011 |
3 | 1100110202220202111011 |
4 | 31022033112212323 |
5 | 212414343100020 |
6 | 10254052214351 |
7 | 1010110522633 |
oct | 151217264673 |
9 | 40422822434 |
10 | 14130440635 |
11 | 5aa12a1213 |
12 | 28a430a3b7 |
13 | 144265009c |
14 | 98094d6c3 |
15 | 57a7ec35a |
hex | 34a3d69bb |
14130440635 has 4 divisors (see below), whose sum is σ = 16956528768. Its totient is φ = 11304352504.
The previous prime is 14130440591. The next prime is 14130440669. The reversal of 14130440635 is 53604403141.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53604403141 = 487 ⋅110070643.
It is a cyclic number.
It is not a de Polignac number, because 14130440635 - 217 = 14130309563 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14130440597 and 14130440606.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1413044059 + ... + 1413044068.
It is an arithmetic number, because the mean of its divisors is an integer number (4239132192).
Almost surely, 214130440635 is an apocalyptic number.
14130440635 is a deficient number, since it is larger than the sum of its proper divisors (2826088133).
14130440635 is an equidigital number, since it uses as much as digits as its factorization.
14130440635 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2826088132.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 14130440635 its reverse (53604403141), we get a palindrome (67734843776).
The spelling of 14130440635 in words is "fourteen billion, one hundred thirty million, four hundred forty thousand, six hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •