Base | Representation |
---|---|
bin | 1100110110100000000000… |
… | …0011111011100001110101 |
3 | 1212000212010220020222121120 |
4 | 3031220000003323201311 |
5 | 3323003122004342401 |
6 | 50015234110334153 |
7 | 2655614363266521 |
oct | 315500003734165 |
9 | 55025126228546 |
10 | 14130443434101 |
11 | 4558761a36385 |
12 | 17026a8aba359 |
13 | 7b6658966a07 |
14 | 36bcba7a6d81 |
15 | 197872b54836 |
hex | cda000fb875 |
14130443434101 has 4 divisors (see below), whose sum is σ = 18840591245472. Its totient is φ = 9420295622732.
The previous prime is 14130443434049. The next prime is 14130443434123. The reversal of 14130443434101 is 10143434403141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14130443434101 - 229 = 14129906563189 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14130443434181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355073905681 + ... + 2355073905686.
It is an arithmetic number, because the mean of its divisors is an integer number (4710147811368).
Almost surely, 214130443434101 is an apocalyptic number.
It is an amenable number.
14130443434101 is a deficient number, since it is larger than the sum of its proper divisors (4710147811371).
14130443434101 is an equidigital number, since it uses as much as digits as its factorization.
14130443434101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4710147811370.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 14130443434101 its reverse (10143434403141), we get a palindrome (24273877837242).
The spelling of 14130443434101 in words is "fourteen trillion, one hundred thirty billion, four hundred forty-three million, four hundred thirty-four thousand, one hundred one".
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