14130551426343 has 8 divisors (see below), whose sum is σ = 20553529347456. Its totient is φ = 8563970561400.

The previous prime is 14130551426339. The next prime is 14130551426351. The reversal of 14130551426343 is 34362415503141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14130551426343 - 2² = 14130551426339 is a prime.

It is a super-3 number, since 3×14130551426343³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14130551426295 and 14130551426304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14130551426323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 214099264003 + ... + 214099264068.

It is an arithmetic number, because the mean of its divisors is an integer number (2569191168432).

Almost surely, 2^{14130551426343} is an apocalyptic number.

14130551426343 is a deficient number, since it is larger than the sum of its proper divisors (6422977921113).

14130551426343 is a wasteful number, since it uses less digits than its factorization.

14130551426343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 428198528085.

The product of its (nonzero) digits is 518400, while the sum is 42.

Adding to 14130551426343 its reverse (34362415503141), we get a palindrome (48492966929484).

The spelling of 14130551426343 in words is "fourteen trillion, one hundred thirty billion, five hundred fifty-one million, four hundred twenty-six thousand, three hundred forty-three".