1413111303241 has 4 divisors (see below), whose sum is σ = 1541575967184. Its totient is φ = 1284646639300.

The previous prime is 1413111303211. The next prime is 1413111303257. The reversal of 1413111303241 is 1423031113141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1413111303241 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1413111303211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64232331955 + ... + 64232331976.

It is an arithmetic number, because the mean of its divisors is an integer number (385393991796).

Almost surely, 2^{1413111303241} is an apocalyptic number.

1413111303241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1413111303241 is a deficient number, since it is larger than the sum of its proper divisors (128464663943).

1413111303241 is a wasteful number, since it uses less digits than its factorization.

1413111303241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128464663942.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1413111303241 its reverse (1423031113141), we get a palindrome (2836142416382).

The spelling of 1413111303241 in words is "one trillion, four hundred thirteen billion, one hundred eleven million, three hundred three thousand, two hundred forty-one".