141311632136555 has 4 divisors (see below), whose sum is σ = 169573958563872. Its totient is φ = 113049305709240.

The previous prime is 141311632136537. The next prime is 141311632136557. The reversal of 141311632136555 is 555631236113141.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 141311632136555 - 2⁸ = 141311632136299 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141311632136557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14131163213651 + ... + 14131163213660.

It is an arithmetic number, because the mean of its divisors is an integer number (42393489640968).

Almost surely, 2^{141311632136555} is an apocalyptic number.

141311632136555 is a deficient number, since it is larger than the sum of its proper divisors (28262326427317).

141311632136555 is an equidigital number, since it uses as much as digits as its factorization.

141311632136555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28262326427316.

The product of its digits is 972000, while the sum is 47.

Adding to 141311632136555 its reverse (555631236113141), we get a palindrome (696942868249696).

The spelling of 141311632136555 in words is "one hundred forty-one trillion, three hundred eleven billion, six hundred thirty-two million, one hundred thirty-six thousand, five hundred fifty-five".