141312220001 has 4 divisors (see below), whose sum is σ = 141313001904. Its totient is φ = 141311438100.

The previous prime is 141312219929. The next prime is 141312220051. The reversal of 141312220001 is 100022213141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 141312220001 - 2¹⁰ = 141312218977 is a prime.

It is a super-2 number, since 2×141312220001² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141312220051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34406 + ... + 532736.

It is an arithmetic number, because the mean of its divisors is an integer number (35328250476).

Almost surely, 2^141312220001 is an apocalyptic number.

It is an amenable number.

141312220001 is a deficient number, since it is larger than the sum of its proper divisors (781903).

141312220001 is an equidigital number, since it uses as much as digits as its factorization.

141312220001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 781902.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 141312220001 its reverse (100022213141), we get a palindrome (241334433142).

The spelling of 141312220001 in words is "one hundred forty-one billion, three hundred twelve million, two hundred twenty thousand, one".