14132030342401 has 4 divisors (see below), whose sum is σ = 14132038113072. Its totient is φ = 14132022571732.

The previous prime is 14132030342377. The next prime is 14132030342429. The reversal of 14132030342401 is 10424303023141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 14132030342401 - 2¹⁷ = 14132030211329 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14132030342401.

It is not an unprimeable number, because it can be changed into a prime (14132030340401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470070 + ... + 5337136.

It is an arithmetic number, because the mean of its divisors is an integer number (3533009528268).

Almost surely, 2^{14132030342401} is an apocalyptic number.

It is an amenable number.

14132030342401 is a deficient number, since it is larger than the sum of its proper divisors (7770671).

14132030342401 is an equidigital number, since it uses as much as digits as its factorization.

14132030342401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7770670.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 14132030342401 its reverse (10424303023141), we get a palindrome (24556333365542).

The spelling of 14132030342401 in words is "fourteen trillion, one hundred thirty-two billion, thirty million, three hundred forty-two thousand, four hundred one".