Base | Representation |
---|---|
bin | 1100110110100101111011… |
… | …0011101110110010100101 |
3 | 1212001000020200100110211201 |
4 | 3031221132303232302211 |
5 | 3323014400423220031 |
6 | 50020055533002501 |
7 | 2656001644466065 |
oct | 315513663566245 |
9 | 55030220313751 |
10 | 14132033023141 |
11 | 45593a8247130 |
12 | 1702a71323431 |
13 | 7b6850095b47 |
14 | 36bdcb94b3a5 |
15 | 197917498d61 |
hex | cda5eceeca5 |
14132033023141 has 16 divisors (see below), whose sum is σ = 15574093933248. Its totient is φ = 12716270512000.
The previous prime is 14132033023133. The next prime is 14132033023187.
14132033023141 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 14132033023141 - 23 = 14132033023133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14132033123141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1777905 + ... + 5605801.
It is an arithmetic number, because the mean of its divisors is an integer number (973380870828).
Almost surely, 214132033023141 is an apocalyptic number.
14132033023141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14132033023141 is a deficient number, since it is larger than the sum of its proper divisors (1442060910107).
14132033023141 is a wasteful number, since it uses less digits than its factorization.
14132033023141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3831332.
The product of its (nonzero) digits is 5184, while the sum is 28.
It can be divided in two parts, 1413203 and 3023141, that added together give a palindrome (4436344).
The spelling of 14132033023141 in words is "fourteen trillion, one hundred thirty-two billion, thirty-three million, twenty-three thousand, one hundred forty-one".
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