Base | Representation |
---|---|
bin | 1100110110100101111101… |
… | …1010100110100101010010 |
3 | 1212001000021101112011220000 |
4 | 3031221133122212211102 |
5 | 3323014411030310023 |
6 | 50020100535230430 |
7 | 2656002130216404 |
oct | 315513732464522 |
9 | 55030241464800 |
10 | 14132043213138 |
11 | 4559402a77014 |
12 | 1702a74818416 |
13 | 7b6852223026 |
14 | 36bdcd040b74 |
15 | 19791830d243 |
hex | cda5f6a6952 |
14132043213138 has 40 divisors (see below), whose sum is σ = 31669717804032. Its totient is φ = 4710164452344.
The previous prime is 14132043213091. The next prime is 14132043213139. The reversal of 14132043213138 is 83131234023141.
14132043213138 is a `hidden beast` number, since 1 + 4 + 1 + 320 + 4 + 321 + 3 + 1 + 3 + 8 = 666.
It is not an unprimeable number, because it can be changed into a prime (14132043213139) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3300370 + ... + 6257517.
Almost surely, 214132043213138 is an apocalyptic number.
14132043213138 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
14132043213138 is an abundant number, since it is smaller than the sum of its proper divisors (17537674590894).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14132043213138 is an equidigital number, since it uses as much as digits as its factorization.
14132043213138 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9567028 (or 9567019 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 36.
Adding to 14132043213138 its reverse (83131234023141), we get a palindrome (97263277236279).
The spelling of 14132043213138 in words is "fourteen trillion, one hundred thirty-two billion, forty-three million, two hundred thirteen thousand, one hundred thirty-eight".
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