141321411443441 has 4 divisors (see below), whose sum is σ = 148759380466800. Its totient is φ = 133883442420084.

The previous prime is 141321411443437. The next prime is 141321411443573. The reversal of 141321411443441 is 144344114123141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141321411443441 - 2² = 141321411443437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141321411443395 and 141321411443404.

It is not an unprimeable number, because it can be changed into a prime (141321411443041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3718984511651 + ... + 3718984511688.

It is an arithmetic number, because the mean of its divisors is an integer number (37189845116700).

Almost surely, 2^{141321411443441} is an apocalyptic number.

It is an amenable number.

141321411443441 is a deficient number, since it is larger than the sum of its proper divisors (7437969023359).

141321411443441 is an equidigital number, since it uses as much as digits as its factorization.

141321411443441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7437969023358.

The product of its digits is 73728, while the sum is 38.

Adding to 141321411443441 its reverse (144344114123141), we get a palindrome (285665525566582).

The spelling of 141321411443441 in words is "one hundred forty-one trillion, three hundred twenty-one billion, four hundred eleven million, four hundred forty-three thousand, four hundred forty-one".