Base | Representation |
---|---|
bin | 100000001000100001101011… |
… | …110110000011111000101111 |
3 | 200112101101102122201220000220 |
4 | 200020201223312003320233 |
5 | 122010420322242211031 |
6 | 1220323025121422423 |
7 | 41524164632161443 |
oct | 4010415366037057 |
9 | 615341378656026 |
10 | 141323413241391 |
11 | 41036a17532207 |
12 | 13a2551119aa13 |
13 | 60b1982393614 |
14 | 26c81381b4823 |
15 | 115122db4d596 |
hex | 80886bd83e2f |
141323413241391 has 4 divisors (see below), whose sum is σ = 188431217655192. Its totient is φ = 94215608827592.
The previous prime is 141323413241377. The next prime is 141323413241393. The reversal of 141323413241391 is 193142314323141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141323413241391 - 215 = 141323413208623 is a prime.
It is a super-2 number, since 2×1413234132413912 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141323413241393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23553902206896 + ... + 23553902206901.
It is an arithmetic number, because the mean of its divisors is an integer number (47107804413798).
Almost surely, 2141323413241391 is an apocalyptic number.
141323413241391 is a deficient number, since it is larger than the sum of its proper divisors (47107804413801).
141323413241391 is an equidigital number, since it uses as much as digits as its factorization.
141323413241391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47107804413800.
The product of its digits is 186624, while the sum is 42.
The spelling of 141323413241391 in words is "one hundred forty-one trillion, three hundred twenty-three billion, four hundred thirteen million, two hundred forty-one thousand, three hundred ninety-one".
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